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X/5X+2=4X-9
We move all terms to the left:
X/5X+2-(4X-9)=0
Domain of the equation: 5X!=0We get rid of parentheses
X!=0/5
X!=0
X∈R
X/5X-4X+9+2=0
We multiply all the terms by the denominator
X-4X*5X+9*5X+2*5X=0
Wy multiply elements
-20X^2+X+45X+10X=0
We add all the numbers together, and all the variables
-20X^2+56X=0
a = -20; b = 56; c = 0;
Δ = b2-4ac
Δ = 562-4·(-20)·0
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3136}=56$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-56}{2*-20}=\frac{-112}{-40} =2+4/5 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+56}{2*-20}=\frac{0}{-40} =0 $
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