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2x^2/2x+77=140
We move all terms to the left:
2x^2/2x+77-(140)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
2x^2/2x-63=0
We multiply all the terms by the denominator
2x^2-63*2x=0
Wy multiply elements
2x^2-126x=0
a = 2; b = -126; c = 0;
Δ = b2-4ac
Δ = -1262-4·2·0
Δ = 15876
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{15876}=126$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-126)-126}{2*2}=\frac{0}{4} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-126)+126}{2*2}=\frac{252}{4} =63 $
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