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X/2X-6=2/X-4
We move all terms to the left:
X/2X-6-(2/X-4)=0
Domain of the equation: 2X!=0
X!=0/2
X!=0
X∈R
Domain of the equation: X-4)!=0We get rid of parentheses
X∈R
X/2X-2/X+4-6=0
We calculate fractions
X^2/2X^2+(-4X)/2X^2+4-6=0
We add all the numbers together, and all the variables
X^2/2X^2+(-4X)/2X^2-2=0
We multiply all the terms by the denominator
X^2+(-4X)-2*2X^2=0
Wy multiply elements
X^2-4X^2+(-4X)=0
We get rid of parentheses
X^2-4X^2-4X=0
We add all the numbers together, and all the variables
-3X^2-4X=0
a = -3; b = -4; c = 0;
Δ = b2-4ac
Δ = -42-4·(-3)·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4}{2*-3}=\frac{0}{-6} =0 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4}{2*-3}=\frac{8}{-6} =-1+1/3 $
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