4(y+1)+7=8(y-1)+6

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Solution for 4(y+1)+7=8(y-1)+6 equation:



4(y+1)+7=8(y-1)+6
We move all terms to the left:
4(y+1)+7-(8(y-1)+6)=0
We multiply parentheses
4y-(8(y-1)+6)+4+7=0
We calculate terms in parentheses: -(8(y-1)+6), so:
8(y-1)+6
We multiply parentheses
8y-8+6
We add all the numbers together, and all the variables
8y-2
Back to the equation:
-(8y-2)
We add all the numbers together, and all the variables
4y-(8y-2)+11=0
We get rid of parentheses
4y-8y+2+11=0
We add all the numbers together, and all the variables
-4y+13=0
We move all terms containing y to the left, all other terms to the right
-4y=-13
y=-13/-4
y=3+1/4

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