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X-42+2X-59+1/4X+21=180
We move all terms to the left:
X-42+2X-59+1/4X+21-(180)=0
Domain of the equation: 4X!=0We add all the numbers together, and all the variables
X!=0/4
X!=0
X∈R
3X+1/4X-260=0
We multiply all the terms by the denominator
3X*4X-260*4X+1=0
Wy multiply elements
12X^2-1040X+1=0
a = 12; b = -1040; c = +1;
Δ = b2-4ac
Δ = -10402-4·12·1
Δ = 1081552
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1081552}=\sqrt{16*67597}=\sqrt{16}*\sqrt{67597}=4\sqrt{67597}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1040)-4\sqrt{67597}}{2*12}=\frac{1040-4\sqrt{67597}}{24} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1040)+4\sqrt{67597}}{2*12}=\frac{1040+4\sqrt{67597}}{24} $
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