3(4t-4)=10t+7+t

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Solution for 3(4t-4)=10t+7+t equation: 



3(4t-4)=10t+7+t

We move all terms to the left:

3(4t-4)-(10t+7+t)=0

We add all the numbers together, and all the variables

3(4t-4)-(11t+7)=0

We multiply parentheses

12t-(11t+7)-12=0

We get rid of parentheses

12t-11t-7-12=0

We add all the numbers together, and all the variables

t-19=0

We move all terms containing t to the left, all other terms to the right

t=19

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