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X-3X+3=3X(X-1)+3X-9
We move all terms to the left:
X-3X+3-(3X(X-1)+3X-9)=0
We add all the numbers together, and all the variables
-2X-(3X(X-1)+3X-9)+3=0
We calculate terms in parentheses: -(3X(X-1)+3X-9), so:We get rid of parentheses
3X(X-1)+3X-9
We add all the numbers together, and all the variables
3X+3X(X-1)-9
We multiply parentheses
3X^2+3X-3X-9
We add all the numbers together, and all the variables
3X^2-9
Back to the equation:
-(3X^2-9)
-3X^2-2X+9+3=0
We add all the numbers together, and all the variables
-3X^2-2X+12=0
a = -3; b = -2; c = +12;
Δ = b2-4ac
Δ = -22-4·(-3)·12
Δ = 148
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{148}=\sqrt{4*37}=\sqrt{4}*\sqrt{37}=2\sqrt{37}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{37}}{2*-3}=\frac{2-2\sqrt{37}}{-6} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{37}}{2*-3}=\frac{2+2\sqrt{37}}{-6} $
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