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X-2+3/5X=14
We move all terms to the left:
X-2+3/5X-(14)=0
Domain of the equation: 5X!=0We add all the numbers together, and all the variables
X!=0/5
X!=0
X∈R
X+3/5X-16=0
We multiply all the terms by the denominator
X*5X-16*5X+3=0
Wy multiply elements
5X^2-80X+3=0
a = 5; b = -80; c = +3;
Δ = b2-4ac
Δ = -802-4·5·3
Δ = 6340
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{6340}=\sqrt{4*1585}=\sqrt{4}*\sqrt{1585}=2\sqrt{1585}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-80)-2\sqrt{1585}}{2*5}=\frac{80-2\sqrt{1585}}{10} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-80)+2\sqrt{1585}}{2*5}=\frac{80+2\sqrt{1585}}{10} $
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