12-2/3(n-6)=28

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Solution for 12-2/3(n-6)=28 equation: 



12-2/3(n-6)=28

We move all terms to the left:

12-2/3(n-6)-(28)=0



Domain of the equation: 3(n-6)!=0

n∈R



We add all the numbers together, and all the variables

-2/3(n-6)-16=0

We multiply all the terms by the denominator


-16*3(n-6)-2=0

Wy multiply elements

-48n(n-2=0

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