88/48+22/5x=25/6x+1

Solution for 88/48+22/5x=25/6x+1 equation:

88/48+22/5x=25/6x+1

We move all terms to the left:

88/48+22/5x-(25/6x+1)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



Domain of the equation: 6x+1)!=0

x∈R


We get rid of parentheses

22/5x-25/6x-1+88/48=0

We calculate fractions


15840x^2/5760x^2+25344x/5760x^2+(-24000x)/5760x^2-1=0

We multiply all the terms by the denominator


15840x^2+25344x+(-24000x)-1*5760x^2=0

Wy multiply elements

15840x^2-5760x^2+25344x+(-24000x)=0

We get rid of parentheses

15840x^2-5760x^2+25344x-24000x=0

We add all the numbers together, and all the variables

10080x^2+1344x=0

a = 10080; b = 1344; c = 0;
Δ = b2-4ac
Δ = 13442-4·10080·0
Δ = 1806336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1806336}=1344$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1344)-1344}{2*10080}=\frac{-2688}{20160}
=-2/15
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1344)+1344}{2*10080}=\frac{0}{20160}
=0
$