X-12(x-10)=4x+8(x-40)

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Solution for X-12(x-10)=4x+8(x-40) equation: 



X-12(X-10)=4X+8(X-40)

We move all terms to the left:

X-12(X-10)-(4X+8(X-40))=0

We multiply parentheses

X-12X-(4X+8(X-40))+120=0



We calculate terms in parentheses: -(4X+8(X-40)), so:

4X+8(X-40)

We multiply parentheses

4X+8X-320

We add all the numbers together, and all the variables

12X-320

Back to the equation:

-(12X-320)



We add all the numbers together, and all the variables

-11X-(12X-320)+120=0

We get rid of parentheses

-11X-12X+320+120=0

We add all the numbers together, and all the variables

-23X+440=0

We move all terms containing X to the left, all other terms to the right

-23X=-440

X=-440/-23

X=19+3/23

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