X-3(x-2)=1x+2(x-10)

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Solution for X-3(x-2)=1x+2(x-10) equation: 



X-3(X-2)=1X+2(X-10)

We move all terms to the left:

X-3(X-2)-(1X+2(X-10))=0

We multiply parentheses

X-3X-(1X+2(X-10))+6=0



We calculate terms in parentheses: -(1X+2(X-10)), so:

1X+2(X-10)

We add all the numbers together, and all the variables

X+2(X-10)

We multiply parentheses

X+2X-20

We add all the numbers together, and all the variables

3X-20

Back to the equation:

-(3X-20)



We add all the numbers together, and all the variables

-2X-(3X-20)+6=0

We get rid of parentheses

-2X-3X+20+6=0

We add all the numbers together, and all the variables

-5X+26=0

We move all terms containing X to the left, all other terms to the right

-5X=-26

X=-26/-5

X=5+1/5

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