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X-10=(3/2X)
We move all terms to the left:
X-10-((3/2X))=0
Domain of the equation: 2X))!=0We add all the numbers together, and all the variables
X!=0/1
X!=0
X∈R
X-((+3/2X))-10=0
We multiply all the terms by the denominator
X*2X))-((-10*2X))+3=0
Wy multiply elements
2X^2-20X=0
a = 2; b = -20; c = 0;
Δ = b2-4ac
Δ = -202-4·2·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-20}{2*2}=\frac{0}{4} =0 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+20}{2*2}=\frac{40}{4} =10 $
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