9(2-3x)-29=8x+-(x-23)

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Solution for 9(2-3x)-29=8x+-(x-23) equation: 



9(2-3x)-29=8x+-(x-23)

We move all terms to the left:

9(2-3x)-29-(8x+-(x-23))=0

We add all the numbers together, and all the variables

9(-3x+2)-(8x+-(x-23))-29=0

We use the square of the difference formula

9(-3x+2)-(8x-(x-23))-29=0

We multiply parentheses

-27x-(8x-(x-23))+18-29=0



We calculate terms in parentheses: -(8x-(x-23)), so:

8x-(x-23)

We get rid of parentheses

8x-x+23

We add all the numbers together, and all the variables

7x+23

Back to the equation:

-(7x+23)



We add all the numbers together, and all the variables

-27x-(7x+23)-11=0

We get rid of parentheses

-27x-7x-23-11=0

We add all the numbers together, and all the variables

-34x-34=0

We move all terms containing x to the left, all other terms to the right

-34x=34

x=34/-34

x=-1

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