X+4x+(4x+12)=345

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Solution for X+4x+(4x+12)=345 equation: 



X+4X+(4X+12)=345

We move all terms to the left:

X+4X+(4X+12)-(345)=0

We add all the numbers together, and all the variables

5X+(4X+12)-345=0

We get rid of parentheses

5X+4X+12-345=0

We add all the numbers together, and all the variables

9X-333=0

We move all terms containing X to the left, all other terms to the right

9X=333

X=333/9

X=37

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