1x+20=6-(2x+5)+8x

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Solution for 1x+20=6-(2x+5)+8x equation: 



1x+20=6-(2x+5)+8x

We move all terms to the left:

1x+20-(6-(2x+5)+8x)=0

We add all the numbers together, and all the variables

x-(6-(2x+5)+8x)+20=0



We calculate terms in parentheses: -(6-(2x+5)+8x), so:

6-(2x+5)+8x

determiningTheFunctionDomain
-(2x+5)+8x+6

We add all the numbers together, and all the variables

8x-(2x+5)+6

We get rid of parentheses

8x-2x-5+6

We add all the numbers together, and all the variables

6x+1

Back to the equation:

-(6x+1)



We get rid of parentheses

x-6x-1+20=0

We add all the numbers together, and all the variables

-5x+19=0

We move all terms containing x to the left, all other terms to the right

-5x=-19

x=-19/-5

x=3+4/5

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