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X+4/3X=56
We move all terms to the left:
X+4/3X-(56)=0
Domain of the equation: 3X!=0We multiply all the terms by the denominator
X!=0/3
X!=0
X∈R
X*3X-56*3X+4=0
Wy multiply elements
3X^2-168X+4=0
a = 3; b = -168; c = +4;
Δ = b2-4ac
Δ = -1682-4·3·4
Δ = 28176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{28176}=\sqrt{16*1761}=\sqrt{16}*\sqrt{1761}=4\sqrt{1761}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-168)-4\sqrt{1761}}{2*3}=\frac{168-4\sqrt{1761}}{6} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-168)+4\sqrt{1761}}{2*3}=\frac{168+4\sqrt{1761}}{6} $
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