4b+7+9b-15=3(2b-5)+28

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Solution for 4b+7+9b-15=3(2b-5)+28 equation: 



4b+7+9b-15=3(2b-5)+28

We move all terms to the left:

4b+7+9b-15-(3(2b-5)+28)=0

We add all the numbers together, and all the variables

13b-(3(2b-5)+28)-8=0



We calculate terms in parentheses: -(3(2b-5)+28), so:

3(2b-5)+28

We multiply parentheses

6b-15+28

We add all the numbers together, and all the variables

6b+13

Back to the equation:

-(6b+13)



We get rid of parentheses

13b-6b-13-8=0

We add all the numbers together, and all the variables

7b-21=0

We move all terms containing b to the left, all other terms to the right

7b=21

b=21/7

b=3

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