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X+3=5/3X-1
We move all terms to the left:
X+3-(5/3X-1)=0
Domain of the equation: 3X-1)!=0We get rid of parentheses
X∈R
X-5/3X+1+3=0
We multiply all the terms by the denominator
X*3X+1*3X+3*3X-5=0
Wy multiply elements
3X^2+3X+9X-5=0
We add all the numbers together, and all the variables
3X^2+12X-5=0
a = 3; b = 12; c = -5;
Δ = b2-4ac
Δ = 122-4·3·(-5)
Δ = 204
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{204}=\sqrt{4*51}=\sqrt{4}*\sqrt{51}=2\sqrt{51}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-2\sqrt{51}}{2*3}=\frac{-12-2\sqrt{51}}{6} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+2\sqrt{51}}{2*3}=\frac{-12+2\sqrt{51}}{6} $
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