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X+31/12X+10=46
We move all terms to the left:
X+31/12X+10-(46)=0
Domain of the equation: 12X!=0We add all the numbers together, and all the variables
X!=0/12
X!=0
X∈R
X+31/12X-36=0
We multiply all the terms by the denominator
X*12X-36*12X+31=0
Wy multiply elements
12X^2-432X+31=0
a = 12; b = -432; c = +31;
Δ = b2-4ac
Δ = -4322-4·12·31
Δ = 185136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{185136}=\sqrt{16*11571}=\sqrt{16}*\sqrt{11571}=4\sqrt{11571}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-432)-4\sqrt{11571}}{2*12}=\frac{432-4\sqrt{11571}}{24} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-432)+4\sqrt{11571}}{2*12}=\frac{432+4\sqrt{11571}}{24} $
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