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X+31/2X+10=46
We move all terms to the left:
X+31/2X+10-(46)=0
Domain of the equation: 2X!=0We add all the numbers together, and all the variables
X!=0/2
X!=0
X∈R
X+31/2X-36=0
We multiply all the terms by the denominator
X*2X-36*2X+31=0
Wy multiply elements
2X^2-72X+31=0
a = 2; b = -72; c = +31;
Δ = b2-4ac
Δ = -722-4·2·31
Δ = 4936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4936}=\sqrt{4*1234}=\sqrt{4}*\sqrt{1234}=2\sqrt{1234}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-2\sqrt{1234}}{2*2}=\frac{72-2\sqrt{1234}}{4} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+2\sqrt{1234}}{2*2}=\frac{72+2\sqrt{1234}}{4} $
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