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X+2=1/6X
We move all terms to the left:
X+2-(1/6X)=0
Domain of the equation: 6X)!=0We add all the numbers together, and all the variables
X!=0/1
X!=0
X∈R
X-(+1/6X)+2=0
We get rid of parentheses
X-1/6X+2=0
We multiply all the terms by the denominator
X*6X+2*6X-1=0
Wy multiply elements
6X^2+12X-1=0
a = 6; b = 12; c = -1;
Δ = b2-4ac
Δ = 122-4·6·(-1)
Δ = 168
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{168}=\sqrt{4*42}=\sqrt{4}*\sqrt{42}=2\sqrt{42}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-2\sqrt{42}}{2*6}=\frac{-12-2\sqrt{42}}{12} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+2\sqrt{42}}{2*6}=\frac{-12+2\sqrt{42}}{12} $
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