3(3n-5)=-5(n-4)+7n

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Solution for 3(3n-5)=-5(n-4)+7n equation: 



3(3n-5)=-5(n-4)+7n

We move all terms to the left:

3(3n-5)-(-5(n-4)+7n)=0

We multiply parentheses

9n-(-5(n-4)+7n)-15=0



We calculate terms in parentheses: -(-5(n-4)+7n), so:

-5(n-4)+7n

We add all the numbers together, and all the variables

7n-5(n-4)

We multiply parentheses

7n-5n+20

We add all the numbers together, and all the variables

2n+20

Back to the equation:

-(2n+20)



We get rid of parentheses

9n-2n-20-15=0

We add all the numbers together, and all the variables

7n-35=0

We move all terms containing n to the left, all other terms to the right

7n=35

n=35/7

n=5

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