X+2(x-3)=6(x+5)

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Solution for X+2(x-3)=6(x+5) equation: 



X+2(X-3)=6(X+5)

We move all terms to the left:

X+2(X-3)-(6(X+5))=0

We multiply parentheses

X+2X-(6(X+5))-6=0



We calculate terms in parentheses: -(6(X+5)), so:

6(X+5)

We multiply parentheses

6X+30

Back to the equation:

-(6X+30)



We add all the numbers together, and all the variables

3X-(6X+30)-6=0

We get rid of parentheses

3X-6X-30-6=0

We add all the numbers together, and all the variables

-3X-36=0

We move all terms containing X to the left, all other terms to the right

-3X=36

X=36/-3

X=-12

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