X+2(x-3)2+2=3(x-1)2-(x+2)2

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Solution for X+2(x-3)2+2=3(x-1)2-(x+2)2 equation: 



X+2(X-3)2+2=3(X-1)2-(X+2)2

We move all terms to the left:

X+2(X-3)2+2-(3(X-1)2-(X+2)2)=0

We multiply parentheses

X+4X-(3(X-1)2-(X+2)2)-12+2=0



We calculate terms in parentheses: -(3(X-1)2-(X+2)2), so:

3(X-1)2-(X+2)2

We multiply parentheses

6X-2X-6-4

We add all the numbers together, and all the variables

4X-10

Back to the equation:

-(4X-10)



We add all the numbers together, and all the variables

5X-(4X-10)-10=0

We get rid of parentheses

5X-4X+10-10=0

We add all the numbers together, and all the variables

X=0

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