2x2=6x+56

Solution for 2x2=6x+56 equation:

2x^2=6x+56

We move all terms to the left:

2x^2-(6x+56)=0

We get rid of parentheses

2x^2-6x-56=0

a = 2; b = -6; c = -56;
Δ = b2-4ac
Δ = -62-4·2·(-56)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-22}{2*2}=\frac{-16}{4}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+22}{2*2}=\frac{28}{4}
=7
$