X+11-(2x+3)=4(x-2)+15

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Solution for X+11-(2x+3)=4(x-2)+15 equation:



X+11-(2X+3)=4(X-2)+15
We move all terms to the left:
X+11-(2X+3)-(4(X-2)+15)=0
We get rid of parentheses
X-2X-(4(X-2)+15)-3+11=0
We calculate terms in parentheses: -(4(X-2)+15), so:
4(X-2)+15
We multiply parentheses
4X-8+15
We add all the numbers together, and all the variables
4X+7
Back to the equation:
-(4X+7)
We add all the numbers together, and all the variables
-1X-(4X+7)+8=0
We get rid of parentheses
-1X-4X-7+8=0
We add all the numbers together, and all the variables
-5X+1=0
We move all terms containing X to the left, all other terms to the right
-5X=-1
X=-1/-5
X=1/5

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