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4/5f=2/5
We move all terms to the left:
4/5f-(2/5)=0
Domain of the equation: 5f!=0We add all the numbers together, and all the variables
f!=0/5
f!=0
f∈R
4/5f-(+2/5)=0
We get rid of parentheses
4/5f-2/5=0
We calculate fractions
=0
f=0/1
f=0
Równanie nie ma rozwiązania
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