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X+1/3X=640
We move all terms to the left:
X+1/3X-(640)=0
Domain of the equation: 3X!=0We multiply all the terms by the denominator
X!=0/3
X!=0
X∈R
X*3X-640*3X+1=0
Wy multiply elements
3X^2-1920X+1=0
a = 3; b = -1920; c = +1;
Δ = b2-4ac
Δ = -19202-4·3·1
Δ = 3686388
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3686388}=\sqrt{4*921597}=\sqrt{4}*\sqrt{921597}=2\sqrt{921597}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1920)-2\sqrt{921597}}{2*3}=\frac{1920-2\sqrt{921597}}{6} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1920)+2\sqrt{921597}}{2*3}=\frac{1920+2\sqrt{921597}}{6} $
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