12(4m-5)+25=21

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Solution for 12(4m-5)+25=21 equation: 



12(4m-5)+25=21

We move all terms to the left:

12(4m-5)+25-(21)=0

We add all the numbers together, and all the variables

12(4m-5)+4=0

We multiply parentheses

48m-60+4=0

We add all the numbers together, and all the variables

48m-56=0

We move all terms containing m to the left, all other terms to the right

48m=56

m=56/48

m=1+1/6

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