X+1/3+1/3x-4+2(1/3x-4)=72

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Solution for X+1/3+1/3x-4+2(1/3x-4)=72 equation: 



X+1/3+1/3X-4+2(1/3X-4)=72

We move all terms to the left:

X+1/3+1/3X-4+2(1/3X-4)-(72)=0



Domain of the equation: 3X!=0

X!=0/3

X!=0

X∈R





Domain of the equation: 3X-4)!=0

X∈R



determiningTheFunctionDomain
X+1/3X+2(1/3X-4)-4-72+1/3=0

We add all the numbers together, and all the variables

X+1/3X+2(1/3X-4)-76+1/3=0

We multiply parentheses

X+1/3X+2X-8-76+1/3=0

We calculate fractions


X+2X-8-76=0

We add all the numbers together, and all the variables

3X-84=0

We move all terms containing X to the left, all other terms to the right

3X=84

X=84/3

X=28

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