(x)=3x+7/7x-3;(x)=6x/7x-3

Solution for (x)=3x+7/7x-3;(x)=6x/7x-3 equation:

(x)=3x+7/7x-3(x)=6x/7x-3

We move all terms to the left:

(x)-(3x+7/7x-3(x))=0


Domain of the equation: 7x-3x)!=0

x∈R


We add all the numbers together, and all the variables

x-(+7/7x)=0

We get rid of parentheses

x-7/7x=0

We multiply all the terms by the denominator


x*7x-7=0

Wy multiply elements

7x^2-7=0

a = 7; b = 0; c = -7;
Δ = b2-4ac
Δ = 02-4·7·(-7)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-14}{2*7}=\frac{-14}{14}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+14}{2*7}=\frac{14}{14}
=1
$