X+1/3+1/3-4+2(1/3x-4)=72

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Solution for X+1/3+1/3-4+2(1/3x-4)=72 equation: 



X+1/3+1/3-4+2(1/3X-4)=72

We move all terms to the left:

X+1/3+1/3-4+2(1/3X-4)-(72)=0



Domain of the equation: 3X-4)!=0

X∈R



determiningTheFunctionDomain
X+2(1/3X-4)-4-72+1/3+1/3=0

We add all the numbers together, and all the variables

X+2(1/3X-4)-76+1/3+1/3=0

We multiply parentheses

X+2X-8-76+1/3+1/3=0

We multiply all the terms by the denominator


X*3+2X*3+1+1-8*3-76*3=0

We add all the numbers together, and all the variables

X*3+2X*3-250=0

Wy multiply elements

3X+6X-250=0

We add all the numbers together, and all the variables

9X-250=0

We move all terms containing X to the left, all other terms to the right

9X=250

X=250/9

X=27+7/9

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