X+(x+1)+(x+2)+(x+3)=134

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Solution for X+(x+1)+(x+2)+(x+3)=134 equation: 



X+(X+1)+(X+2)+(X+3)=134

We move all terms to the left:

X+(X+1)+(X+2)+(X+3)-(134)=0

We get rid of parentheses

X+X+X+X+1+2+3-134=0

We add all the numbers together, and all the variables

4X-128=0

We move all terms containing X to the left, all other terms to the right

4X=128

X=128/4

X=32

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