4u-2+2(3u+5)=-4(u+1)

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Solution for 4u-2+2(3u+5)=-4(u+1) equation: 



4u-2+2(3u+5)=-4(u+1)

We move all terms to the left:

4u-2+2(3u+5)-(-4(u+1))=0

We multiply parentheses

4u+6u-(-4(u+1))+10-2=0



We calculate terms in parentheses: -(-4(u+1)), so:

-4(u+1)

We multiply parentheses

-4u-4

Back to the equation:

-(-4u-4)



We add all the numbers together, and all the variables

10u-(-4u-4)+8=0

We get rid of parentheses

10u+4u+4+8=0

We add all the numbers together, and all the variables

14u+12=0

We move all terms containing u to the left, all other terms to the right

14u=-12

u=-12/14

u=-6/7

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