X+(72)/(x-9)=(8x)/(x-9)

Solution for X+(72)/(x-9)=(8x)/(x-9) equation:

X+(72)/(X-9)=(8X)/(X-9)

We move all terms to the left:

X+(72)/(X-9)-((8X)/(X-9))=0


Domain of the equation: (X-9)!=0

We move all terms containing X to the left, all other terms to the right

X!=9

X∈R



Domain of the equation: (X-9))!=0

X∈R


We calculate fractions


X+72X/((X-9)*(X-9)))+(-(8X*(X-9))/((X-9)*(X-9)))=0


We calculate terms in parentheses: -(8X*(X-9))/((X-9)*(X-9))), so:

8X*(X-9))/((X-9)*(X-9))

We multiply all the terms by the denominator


8X*(X-9))

We multiply parentheses

8X^2-72X^2

We add all the numbers together, and all the variables

-64X^2

Back to the equation:

-(-64X^2)


We get rid of parentheses

64X^2+X+72X/((X-9)*(X-9)))+(=0

We multiply all the terms by the denominator


64X^2*((X-9)*(X-9)))+(+X*((X-9)*(X-9)))+(+72X=0

We add all the numbers together, and all the variables

64X^2*((X-9)*(X-9)))+(+72X+X*((X-9)*(X-9)))+(=0