2(3x-2)+3=3(2x+1)-4

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Solution for 2(3x-2)+3=3(2x+1)-4 equation: 



2(3x-2)+3=3(2x+1)-4

We move all terms to the left:

2(3x-2)+3-(3(2x+1)-4)=0

We multiply parentheses

6x-(3(2x+1)-4)-4+3=0



We calculate terms in parentheses: -(3(2x+1)-4), so:

3(2x+1)-4

We multiply parentheses

6x+3-4

We add all the numbers together, and all the variables

6x-1

Back to the equation:

-(6x-1)



We add all the numbers together, and all the variables

6x-(6x-1)-1=0

We get rid of parentheses

6x-6x+1-1=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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