X+(7/5)x=48

Solution for X+(7/5)x=48 equation:

X+(7/5)X=48

We move all terms to the left:

X+(7/5)X-(48)=0


Domain of the equation: 5)X!=0

X!=0/1

X!=0

X∈R


We add all the numbers together, and all the variables

X+(+7/5)X-48=0

We multiply parentheses

7X^2+X-48=0

a = 7; b = 1; c = -48;
Δ = b2-4ac
Δ = 12-4·7·(-48)
Δ = 1345
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{1345}}{2*7}=\frac{-1-\sqrt{1345}}{14}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{1345}}{2*7}=\frac{-1+\sqrt{1345}}{14}
$