x+5/12=3(x+1)/20

Solution for x+5/12=3(x+1)/20 equation:

x+5/12=3(x+1)/20

We move all terms to the left:

x+5/12-(3(x+1)/20)=0

We calculate fractions


x+(-(3(x+1)*12)/()+()/()=0


We calculate terms in parentheses: +(-(3(x+1)*12)/()+()/(), so:

-(3(x+1)*12)/()+()/(

We add all the numbers together, and all the variables

-(3(x+1)*12)/()+1

We multiply all the terms by the denominator


-(3(x+1)*12)+1*()


We calculate terms in parentheses: -(3(x+1)*12), so:

3(x+1)*12

We multiply parentheses

36x+36

Back to the equation:

-(36x+36)


We add all the numbers together, and all the variables

-(36x+36)

We get rid of parentheses

-36x-36

Back to the equation:

+(-36x-36)


We get rid of parentheses

x-36x-36=0

We add all the numbers together, and all the variables

-35x-36=0

We move all terms containing x to the left, all other terms to the right

-35x=36

x=36/-35

x=-1+1/35