X*5x=96

Solution for X*5x=96 equation:

X*5X=96

We move all terms to the left:

X*5X-(96)=0

Wy multiply elements

5X^2-96=0

a = 5; b = 0; c = -96;
Δ = b2-4ac
Δ = 02-4·5·(-96)
Δ = 1920
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1920}=\sqrt{64*30}=\sqrt{64}*\sqrt{30}=8\sqrt{30}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{30}}{2*5}=\frac{0-8\sqrt{30}}{10}
=-\frac{8\sqrt{30}}{10}
=-\frac{4\sqrt{30}}{5}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{30}}{2*5}=\frac{0+8\sqrt{30}}{10}
=\frac{8\sqrt{30}}{10}
=\frac{4\sqrt{30}}{5}
$