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X*4-3/2X=0
Domain of the equation: 2X!=0Wy multiply elements
X!=0/2
X!=0
X∈R
4X-3/2X=0
We multiply all the terms by the denominator
4X*2X-3=0
Wy multiply elements
8X^2-3=0
a = 8; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·8·(-3)
Δ = 96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{96}=\sqrt{16*6}=\sqrt{16}*\sqrt{6}=4\sqrt{6}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{6}}{2*8}=\frac{0-4\sqrt{6}}{16} =-\frac{4\sqrt{6}}{16} =-\frac{\sqrt{6}}{4} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{6}}{2*8}=\frac{0+4\sqrt{6}}{16} =\frac{4\sqrt{6}}{16} =\frac{\sqrt{6}}{4} $
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