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2(3x-5)+2(5x+6)=258
We move all terms to the left:
2(3x-5)+2(5x+6)-(258)=0
We multiply parentheses
6x+10x-10+12-258=0
We add all the numbers together, and all the variables
16x-256=0
We move all terms containing x to the left, all other terms to the right
16x=256
x=256/16
x=16
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