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X(X+1)=506
We move all terms to the left:
X(X+1)-(506)=0
We multiply parentheses
X^2+X-506=0
a = 1; b = 1; c = -506;
Δ = b2-4ac
Δ = 12-4·1·(-506)
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2025}=45$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-45}{2*1}=\frac{-46}{2} =-23 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+45}{2*1}=\frac{44}{2} =22 $
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