1/2x+3=2(2/3+3x)

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Solution for 1/2x+3=2(2/3+3x) equation: 



1/2x+3=2(2/3+3x)

We move all terms to the left:

1/2x+3-(2(2/3+3x))=0



Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R





Domain of the equation: 3+3x))!=0

We move all terms containing x to the left, all other terms to the right

3x))!=-3

x!=-3/1

x!=-3

x∈R



We add all the numbers together, and all the variables

1/2x-(2(+3x+2/3))+3=0

We calculate fractions


()/6x^2+(-(2(+3x+2*2x)/6x^2+3=0

We calculate fractions

We do not support expression: x^4

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