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X(8+2)+3=2(5+X)+5(X-1)-6
We move all terms to the left:
X(8+2)+3-(2(5+X)+5(X-1)-6)=0
We add all the numbers together, and all the variables
X10-(2(X+5)+5(X-1)-6)+3=0
We add all the numbers together, and all the variables
X^10-(2(X+5)+5(X-1)-6)+3=0
We calculate terms in parentheses: -(2(X+5)+5(X-1)-6), so:We do not support eXpression: X^10
2(X+5)+5(X-1)-6
We multiply parentheses
2X+5X+10-5-6
We add all the numbers together, and all the variables
7X-1
Back to the equation:
-(7X-1)
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