2x+10=-2x+2x(2x+5)

Solution for 2x+10=-2x+2x(2x+5) equation:

2x+10=-2x+2x(2x+5)

We move all terms to the left:

2x+10-(-2x+2x(2x+5))=0


We calculate terms in parentheses: -(-2x+2x(2x+5)), so:

-2x+2x(2x+5)

We multiply parentheses

4x^2-2x+10x

We add all the numbers together, and all the variables

4x^2+8x

Back to the equation:

-(4x^2+8x)


We get rid of parentheses

-4x^2+2x-8x+10=0

We add all the numbers together, and all the variables

-4x^2-6x+10=0

a = -4; b = -6; c = +10;
Δ = b2-4ac
Δ = -62-4·(-4)·10
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-14}{2*-4}=\frac{-8}{-8}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+14}{2*-4}=\frac{20}{-8}
=-2+1/2
$