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X(6-3X)=4X-1
We move all terms to the left:
X(6-3X)-(4X-1)=0
We add all the numbers together, and all the variables
X(-3X+6)-(4X-1)=0
We multiply parentheses
-3X^2+6X-(4X-1)=0
We get rid of parentheses
-3X^2+6X-4X+1=0
We add all the numbers together, and all the variables
-3X^2+2X+1=0
a = -3; b = 2; c = +1;
Δ = b2-4ac
Δ = 22-4·(-3)·1
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-4}{2*-3}=\frac{-6}{-6} =1 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+4}{2*-3}=\frac{2}{-6} =-1/3 $
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