0.6x(x+20)+1.2x=93

Solution for 0.6x(x+20)+1.2x=93 equation:

0.6x(x+20)+1.2x=93

We move all terms to the left:

0.6x(x+20)+1.2x-(93)=0

We add all the numbers together, and all the variables

1.2x+0.6x(x+20)-93=0

We multiply parentheses

0x^2+1.2x+0x-93=0

We add all the numbers together, and all the variables

x^2+2.2x-93=0

a = 1; b = 2.2; c = -93;
Δ = b2-4ac
Δ = 2.22-4·1·(-93)
Δ = 376.84
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.2)-\sqrt{376.84}}{2*1}=\frac{-2.2-\sqrt{376.84}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.2)+\sqrt{376.84}}{2*1}=\frac{-2.2+\sqrt{376.84}}{2}
$