(5y+6)(7y+2)=0

Solution for (5y+6)(7y+2)=0 equation:

(5y+6)(7y+2)=0

We multiply parentheses ..

(+35y^2+10y+42y+12)=0

We get rid of parentheses

35y^2+10y+42y+12=0

We add all the numbers together, and all the variables

35y^2+52y+12=0

a = 35; b = 52; c = +12;
Δ = b2-4ac
Δ = 522-4·35·12
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(52)-32}{2*35}=\frac{-84}{70}
=-1+1/5
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(52)+32}{2*35}=\frac{-20}{70}
=-2/7
$