X(4x+8)=96

Solution for X(4x+8)=96 equation:

X(4X+8)=96

We move all terms to the left:

X(4X+8)-(96)=0

We multiply parentheses

4X^2+8X-96=0

a = 4; b = 8; c = -96;
Δ = b2-4ac
Δ = 82-4·4·(-96)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-40}{2*4}=\frac{-48}{8}
=-6
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+40}{2*4}=\frac{32}{8}
=4
$